0=3[x-(3-x)]-5(x+1)

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Solution for 0=3[x-(3-x)]-5(x+1) equation:


Simplifying
0 = 3[x + -1(3 + -1x)] + -5(x + 1)
0 = 3[x + (3 * -1 + -1x * -1)] + -5(x + 1)
0 = 3[x + (-3 + 1x)] + -5(x + 1)

Reorder the terms:
0 = 3[-3 + x + 1x] + -5(x + 1)

Combine like terms: x + 1x = 2x
0 = 3[-3 + 2x] + -5(x + 1)
0 = [-3 * 3 + 2x * 3] + -5(x + 1)
0 = [-9 + 6x] + -5(x + 1)

Reorder the terms:
0 = -9 + 6x + -5(1 + x)
0 = -9 + 6x + (1 * -5 + x * -5)
0 = -9 + 6x + (-5 + -5x)

Reorder the terms:
0 = -9 + -5 + 6x + -5x

Combine like terms: -9 + -5 = -14
0 = -14 + 6x + -5x

Combine like terms: 6x + -5x = 1x
0 = -14 + 1x

Solving
0 = -14 + 1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
0 + -1x = -14 + 1x + -1x
Remove the zero:
-1x = -14 + 1x + -1x

Combine like terms: 1x + -1x = 0
-1x = -14 + 0
-1x = -14

Divide each side by '-1'.
x = 14

Simplifying
x = 14

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